Chemistry, asked by Hasti152002, 1 year ago

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Give electronic configuration of Rb(37) and Sr(38)

Answers

Answered by itraa2000
1
Rb(37) electronic configuration
[Kr] 5s1
(2, 8, 18, 8, 1).
Sr(38)electronic configuration [Kr]5s2
(2, 8, 18, 8, 2).

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Answered by Anonymous
1
Rb(37)=1s^2,2s^2,2p^6,3s^2,3p^6,3d^10,4s^24,p^6,5s^1

Sr(38)=1s^2,2s^2,2p^6,3s^2,3p^6,3d^10,4s^2,4p^6, 5s^2

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