Question

all trigonometry formulas​

Answer 1

Answer:

sin theta P/H

cos theta B/H

tan theta P/B

cosec theta H/P

sec theta B/H

cot theta B/P

sin2 theta + cos2 theta = 1

cos2 theta+ sec2 theta = 1

cosec2 theta + cot2 theta = 1

sin(90-A)=cosA

cos(90-A)=sinA

tan(90-A)=cotA

cot(90-A)=tanA

cosec(90-A)=secA

sec(90-A)=cosecA

Step-by-step explanation:

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Answer 2

Answer:

sin A= P/H, cos A= B/H, tan A= P/B

cosec A= 1/sinA= H/P, sec A= 1/cos A= H/B, cot A= 1/tan A= B/P

sin( 90° - A) = cos A,

cos(90°-A)= sin A,

tan(90°-A)= cot A,

cot(90°-A)= tan A,

sec(90°-A)= cosec A,

cosec(90°-A)= sec A

cos2 A + sin2 A = 1

1 + tan2 A = sec2 A

1 + cot2 A = cosec2 A