alpha and beta are the zeros of the polynomial 2x^2-7x+6=0. form in equation whose zeros are 1/alpha and 1/beta
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alpha*beta=3
1/alpha*beta=1/3
1/alpha + 1/ beta = (alpha+ beta)/ alpha*beta
=7/2*(3)=7/6
ans is
x^2-7/6(x)+1/3=0
6x^2-7(x)+2=0
1/alpha*beta=1/3
1/alpha + 1/ beta = (alpha+ beta)/ alpha*beta
=7/2*(3)=7/6
ans is
x^2-7/6(x)+1/3=0
6x^2-7(x)+2=0
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