alpha, beeta and gamma are zeroes f the cubic polynomial x3-2x2×qx-r. If alpha + beta = 0 then show that 2q=r
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Answered by
216
Alpha + beeta + Gama =2
0+ gama = 2
Gama=2
Alpha beeta +beeta gama + gama alpha = q
Alpha beeta + gama(alpha + beeta) = q
Alpha beeta + 0 = q
Alpha beeta =q
Alpha *beeta*gama= r
q *gama =r
q *2= r
2q=r
0+ gama = 2
Gama=2
Alpha beeta +beeta gama + gama alpha = q
Alpha beeta + gama(alpha + beeta) = q
Alpha beeta + 0 = q
Alpha beeta =q
Alpha *beeta*gama= r
q *gama =r
q *2= r
2q=r
Anjaliwanode:
plz give me step by step solutions
Answered by
96
Answer:
Step-by-step explanation:
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BY MOHAMMAD RUMAN STUDENT OF EMMAMNUEL MISSION HIGH SCHOOL CLASS 10
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