Question

Am element having bcc structure has unit cell edge 400pm then density of element is

Answer 1

Edge length, a = 400 pm = 400×10-10 cm

Since it is bcc arrangement,
Number of atoms in the unit cell, Z = 2
Atomic mass of the element, M = 100 g

Density = Z×M

a3×N0
Density = 2×100
(400×10−10)
3× 6.022×1023

 = 5.18 g cm-3

Answer 2

Answer:

Explanation:

Edge length, a = 400 pm = 400×10-10 cm

Since it is bcc arrangement,

Number of atoms in the unit cell, Z = 2

Atomic mass of the element, M = 100 g

Density = Z×M

a3×N0

Density = 2×100

(400×10−10)

3× 6.022×1023

 = 5.18 g cm-3