A lens has a power of -1.25d what is the focal lenght and nature of the lwns
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P = -1.25d
F = 1/p
F= 1/-1.25
F = -100/125
F =-0.8m
F = -80 cm
Since focal length I still negatives it is a concave or diverging lens
F = 1/p
F= 1/-1.25
F = -100/125
F =-0.8m
F = -80 cm
Since focal length I still negatives it is a concave or diverging lens
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