Question

Amar has only 3 denominations of coinsie, '1, 2, and '5. If he has a total of 40 coins and the total amount of 130, the maximum
number of 5 coins he can have, is
​

Answer 1

Answer:

max 5 unit coins=22

Step-by-step explanation:

let there are x,y and z coins of 1,2 and 5

then x+y+z=40

and x+2y+5z=130

on subtraction

y+4z=90

4z=90-y

z=(90-y)/4

x,y are natural numbers

x is maximum for y is min

for 90-y to be divisible by 4

y min=2

then

z=(90-2)/4=22