Math, asked by shrishtikatar6584, 1 year ago

Amar was as old as Anthony is now, when Akbar was as old as Anthony was 3 years ago . If the sum of their present age is 37 years and the ratio of present ages if Akbar and Anthony is 6:5, how much percent more is the sum of the ages of Amar and Akbar more than the sum of present ages of Amar and Anthony?

Answers

Answered by TooFree
2

Answer:

8%


Step-by-step explanation:

Define x:

Let Anthony be x years old now


When Akbar = x - 3, Amar = x years old

⇒ Difference in their age is 3.

⇒ Amar is 3 years older than Akbar


The ratio of Akbar and Anthony is 6:5

⇒ Akbar = 6/5 x


Since Amar is 3 years older than Akbar

⇒ Amar = 6/5 x + 3


Solve x:

Their total age is 37

x + 6/5 x + 6/5 x + 3 = 37

17/5 x =34

x = 10


Find their age:

Anthony = x = 10 years old

Akbar = 6/5 x = 6/5 (10) + 12 years old

Amar = 6/5 x + 3 = 5/6 (10) + 3 = 15 years old


Find the sum of Amar and Akbar

Sum = 12 + 15 = 27


Find the sum of Amar and Anthony:

Sum = 15 + 10 = 25


Find the difference:

Difference = 27 - 25 = 2


Find the percentage difference:

Percentage difference = 2/25 x 100 = 8%


Answer: 8%



Answered by 1074064
0

Answer:

8%

Step-by-step explanation:

Because

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