among three consecutive positive even no. the sum of 2/5of the first and half of the second is 11 less than the thirdno.find those three no.
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Answer:
The numbers are 95, 96 and 97.
Step-by-step explanation:
Let the first no. be x.
Thus, the other two consecutive nos. will be x + 1 and x + 1 + 1 => x + 2.
Now, acc. to ques,
(2/5)x + (x + 1)/2 = (x + 2) - 11
=> 2x/5 + (x + 1)/2 = x + 2 - 11
=> [(2x)*2 + (x + 1)*5]/10 = x - 9
=> [(4x) + (5x + 5)]/10 = x - 9
=> 4x + 5x + 5 = (x - 9)*10
=> 9x + 5 = 10x - 90
=> 10x - 9x = 90 + 5 (Signs change to their inverse while switching sides in an equation)
∴ x = 95
So, the first consecutive number is 95. From this, the second and third number are x + 1 = 95 + 1 => 96 and x + 2 = 95 + 2 => 97 respectively.
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