Question

among three consecutive positive even no. the sum of 2/5of the first and half of the second is 11 less than the thirdno.find those three no.​

Answer 1

Answer:

The numbers are 95, 96 and 97.

Step-by-step explanation:

Let the first no. be x.

Thus, the other two consecutive nos. will be x + 1 and x + 1 + 1 => x + 2.

Now, acc. to ques,

(2/5)x + (x + 1)/2 = (x + 2) - 11

=> 2x/5 + (x + 1)/2 = x + 2 - 11

=> [(2x)*2 + (x + 1)*5]/10 = x - 9

=> [(4x) + (5x + 5)]/10 = x - 9

=> 4x + 5x + 5 = (x - 9)*10

=> 9x + 5 = 10x - 90

=> 10x - 9x = 90 + 5           (Signs change to their inverse while switching sides in an equation)

∴ x = 95

So, the first consecutive number is 95. From this, the second and third number are x + 1 = 95 + 1 => 96 and x + 2 = 95 + 2 => 97 respectively.