among two supplementary angles the measure of the larger angle is 36 degree more than the measure of the smaller find their measures
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let angles are x and 36+x;
x+36+x=180
x=144/2=72deg. and x+36=108deg.
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Let the measure of the supplementary angles be x and (x + 36). ⇒ (x) + (x + 36) = 180° ⇒ 2x + 36 = 180° ⇒ 2x = 144° ⇒ x = 72°Therefore, measures of the supplementary angles are 72° and (72 + 36) i.e. 108°.
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