Question

amount of heat energy required to raise the temperature of 5 kg water from 20 degree to 100 degre​

Answer 1

Explanation:

Quantity of heat required to raise 5 kg of water from 20 0C to 1000C is given by the formula:Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.) For water, the value of . C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 OC

Answer 2

Answer:

1.68×10^6J

Explanation:

Formula of heat capacity= c = ΔQ/mΔT

ΔT=100-20=80°C or 80K

m=5kg

c(heat capacity of water) = 4200J/kg

ΔQ=mcΔT

ΔQ=5×4200×80=1.68×10^6J