Question

&
a. Find the value of m so that the point A(1, 2) lies on the locus
( y^2-2x-my+5=0​

Answer 1

A has coordinates 1 n 2

which means

x=1 y=2

by substituting these values in the

equation we will gwt the valur of m

y²-2x-my+5=0

2²-2(1)-m(2)+5=0

4-2-2m+5=0

7-2m=0

-2m=-7 (minus will cancel out)

2m=7

m=7/2

hope it helps uh....