Question

find the values of a,b,c such that the numbers a,7,b,23 and c are in Arthimetic progression

Answer 1

b=(23+7)/2=15

a=7*2-15=-1

c= 23*2-15= 31

Answer 2

Answer:

Step-by-step explanation:

a=t1 7=t2 b=t3 23=t4 c=t5

T2=7=a+d

T4=23=a+3d

a+d=7

- - -

a+3d=23

2d=16

d=8

Sinice a+d=7

a=7-8

=-1

b=a+2d

-1+2 (8)=15

c=a+4d

-1+4 (8)=31