An acorn falls from a tree and hits the ground in 0.8 s. How far did the acorn fall . Use g = 9.8 m/s^2. Round your final result to the nearest tenth.
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Answer:
3m
Explanation:
s=ut + 1/2*a*t^2
here u=0 as acorn was initially at rest
t=0.8sec, a=g=9.8m/s^2
s=0+1/2*9.8*(0.8)^2
s=3.316m
on rounding off
s=3m
here the initial position of acorn is considered as origin and positive axis is towards the earth
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