Math, asked by CarterTim, 1 year ago

An aeroplane flying horizontally 1 km above ground is observed at an elevation of 60° . After 10 seconds elevation is observed to be 30°. Find speed in km/h

Answers

Answered by 9159ammu

When the elevation was 60, distance of the point of observation to the point on the groundbelow the plane = 1xcot60 = 1/?3 km Similarly when the angle becomes 30, distance becomes = 1xcot30 = ?3 km So, distance travelled = ?3 -1/?3 km = 2/?3 km time taken = 10sec = 10/3600 hr hence speed = distance / time = 2x3600/10x?3 = 720/?3 km/hr = 415.7 km/hr

CarterTim: whats does '?' used for in answer

CarterTim: what is

QwertyZoom: Pretty sure that ? was supposed to be a square root symbol

CarterTim: yeah just figured that out. Cheers tho :)

CarterTim: and it was supposed to be tan instead of cot i think

QwertyZoom: No, he used cot values instead of tan

QwertyZoom: Idk why, but ok

CarterTim: i just solved using tan got correct answer lol

QwertyZoom: Yeah it doesn't really make any difference, I find it easier to use tan

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