Question

An aeroplane flying horizontally at height of 0.49km with velocity 98m/s released a bomb on reaching the ground, velocity of bomb is

Answer 1

Hey mate,

● Answer-
v = 98√2 m/s

● Explanation-
Velocity of the bomb has two components.

Horizontal component is same as that of aeroplane.
vx = 98 m/s

Vertical component is given by-
vy^2 = u^2 + 2gh
vy^2 = 0^2 + 2×9.8×490
vy = 98 m/s

Resultant velocity
v = √(vx^2 + vy^2)
v = √(98^2 + 98^2)
v = 98√2 m/s.

Velocity of the bomb is 98√2 m/s.

Hope that is all...

Answer 2

Answer:

98√2ms-1

Explanation:

thank you

for tis is anspwper