An aeroplane is flying horizontally from west to east with velocity of 900 km/hr . Calculate the potential difference developed between the ends of its wings having a span of 20 m . The horizontal component of the Earth's magnetic field is 5 × 10^-4 (power) T and the angle of dip is 30° .
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Potential difference developed between the ends of its wings e = Blv
Given; velocity v = 900km/hr = 250m/s
The horizontal component of Earth's Magnetic Field = 5× 10^-4 T
wing spam (l) = 20m
The vertical component of Earth's Magnetic Field
BV = BH tanδ
= 5 × 10^-4 ( tan 30°) T
Therefore;
The potential difference, e
= 5 × 10^-4 ( tan 30°) × 20 × 250
e = 5 × 10^-4 × 20 × 250
√3
e = 1.44 V
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