Question

An aeroplane is flying horizontally with a velocity of 600 km per hour at a height of 1960 m when it is vertically at a point a on the ground is released from the bomb strike the ground at point b the distance a b is

Answer 1

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Answer 2

Answer:

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Explanation:

see in the question its given:

Velocity= 600Km/hr = 600x1000/3600 m/s=166.66m/s

Ht=1960m.

To Find: The range of the projectile (R).

Its actually a Projetile motion .

For a projectile Ht=1/2*g*t*t.There fore we get t= 20s.

R=V*t=166.66*20=3333.33m/s=3.333Km/hr.