Math, asked by applehoney5017, 1 year ago

An aeroplane acceleratesonaccelerates on the the run way at 3.20m/square for 32.8seconds until it finally lifts off the ground.determine the distance travelled before take off

Answers

Answered by saswatpatra
0

the initial velocity = 0 m /s.


acceleration = 3.20 m / s^2


time = 32.8 s


According to laws of motion.


s = ut + 1/2 at ^2


s = 1/2 at²


s=1/2(3.20)(32.8)²


s= 1721.344 m


the distance traveled before takeoff is 1731.3m




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