An aeroplane acceleratesonaccelerates on the the run way at 3.20m/square for 32.8seconds until it finally lifts off the ground.determine the distance travelled before take off
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the initial velocity = 0 m /s.
acceleration = 3.20 m / s^2
time = 32.8 s
According to laws of motion.
s = ut + 1/2 at ^2
s = 1/2 at²
s=1/2(3.20)(32.8)²
s= 1721.344 m
the distance traveled before takeoff is 1731.3m
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