Physics, asked by noname14, 1 year ago

an aeroplane lands 180km/h and stops after 1.5min calculate retardition and distance travelled by aeroplane before coming to rest?


gouravmahore: answer is 2250 meters
noname14: how
helpme10: yes ...i did one major mistake
helpme10: i.e while applying second eq. a is taken in negative
gouravmahore: yeah i was wrong

Answers

Answered by lucky1773
2
180÷1.5 =12minutes to land

noname14: see the question i asked retardition and distance...
Answered by helpme10
7
Hey dear here is your answer!!!!!

According to given question :-
u= 180km/hr = 50m/s
v= 0
t = 1.5min = 9sec
s=?
a=?

Using first equation of motion..

v= u + at
0 = 50+a(9)
-50/9 = a
a = -5.555 m/s^2

Therefore restardation is 5.5m/s^2

Using second eq. of motion ....

s = ut + 1/2 at^2
s = 50*9 + 1/2(5.6)(81)
s= 450+ 226.8
s= 676.8 m

Distance is 677 m

Hope it helps u dear.......

helpme10: Thanks for marking
helpme10: pardon if any calculation is wrong
helpme10: but method is correct
helpme10: one mistake
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