An aeroplane leaves an airport and flies due north at 300 km/h . At the same time, another aeroplane leaves the same Airport and flies due west at 400 km/h . How far apart the two aeroplanes would be after 1 1/2 hours.
Answers
Answer:
750 km
Step-by-step explanation:
Distance traveled by aeroplane in 1 1/2 = 3/2 hours towards north direction
=> 300 * 3/2
=> 150*3
=> 450 km
So AB = 450 m.
Distance travelled by aeroplane in 3/2 hours towards north direction =
=> 400*3/2
=> 200*3
=> 600 km
So BC = 600 km.
Now from Pythagorus theorem
AC^2 = AB^2 + BC^2
=> AC^2 = (450)^2 + (650)^2
=> AC^2 = 202500 + 360000
=> AC^2 = 562500
=> AC = √562500
=> AC = 750 m.
Hence, distance between two planes after 3/2 hours = 750 km.
#Hope my answer helped you.
Answer:
750 km in one and half hour
Step-by-step explanation:
In one hour the planes travel 300km and 400km respectively, if those travel an extra half an hour then it's value will be added by half so the value must be taken in one and half hour so 450km and 600km are taken.
so the final answer is 750 km in one and half an hour
