Question

an aeroplane left 50min later than its schedule time and in order to reach its destination,1250km away in time it had to increase its speed by 250km/hr from s usaul speed find its usual speed

Answer 1

hye ans is simple
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distance= 1250 (given)
let the speed be (x)
usual speed is T1
T1=DIS./SPEED
T1= 1250/X 
if he increased speed by 250km/hr
T2=1250/x + 250
50/60 hr less than usual time
1250/ x + 250 = 1250/ x-50/60
1250/x+250 = 1250/x-5/6
11250/ x+250= 7500-5x/6x
x^2 +1250x+375000
 find the value of x
here is ur ans