Question

an aeroplane takes off at an angle of 30 degree to the horizontal if component of its velocity along the horizontal is 250 km per hour what is the actual velocity find also the vertical component of the velocity

Answer 1

Let the velocity of the plane be v m/s.

Horizontal component of the velocity = vcos 30° = 200
=> v = 400 =231 Km/hr
Vertical component of the velocity =
Vsin 30° = v = 115.47 Km/hr
2

Answer 2

$\huge {\bf {\underline {Question}}}$

An aeroplane takes off at an angle of 30 degree to the horizontal. if the component of its velocity along teh horizontal is 250 km/hr, what is the actual velocity. find also its vertical component.

$\huge {\bf {\underline {Answer}}}$

Let the velocity of the plane be V m/s.

Horizontal component of velocity =

$V cos 30° = 250 km/h \\ \implies V \frac {\sqrt {3}}{2} = 250 \\ \implies V = \frac {250 \times 2}{\sqrt {3}} \\ \implies V = \frac {500}{\sqrt {3}} \\ \implies V = \frac {500}{1.732} \\ \implies V = 288.7 \: km/h$

Vertical component of velocity =

$V sin 30° = \frac {V}{2} = \frac {288.7}{2} = 144.35\:km/h$

Hope it helps dear....