An air bubble raising from the bottom to the surface of a lake doubles its diameter. If the atmospheric pressure is 76 cm of Hg, What is the depth of water in the lake? please answer with proper explanation
Answers
Answer:
As volume of air bubble becomes double on reaching the surface of lake, hence its pressure becomes half. Since on the lake, the pressure is equal to the atmospheric pressure, hence the pressure of air inside the bubble at the depth of lake = 2 atmospheric pressure = atmospheric pressure + pressure due to column of water h. thus <br>
of water
76 cm of Hg = h cm
= 76 cm of Hg
=76 xx 13.6 cm of water
=1033.6 cm = 10.34 m
As volume of air bubble becomes double on reaching the surface of lake, hence its pressure becomes half. Since on the lake, the pressure is equal to the atmospheric pressure, hence the pressure of air inside the bubble at the depth of lake = 2 atmospheric pressure = atmospheric pressure + pressure due to column of water h. thus <br>
of water
76 cm of Hg = h cm
= 76 cm of Hg
=76 xx 13.6 cm of water
=1033.6 cm = 10.34 m
I hope it's helpful to you
follow me