Physics, asked by ramadevimeruva, 2 months ago

An air bubble raising from the bottom to the surface of a lake doubles its diameter. If the atmospheric pressure is 76 cm of Hg, What is the depth of water in the lake? please answer with proper explanation

Answers

Answered by Dashsnehaswarupa2006
1

Answer:

As volume of air bubble becomes double on reaching the surface of lake, hence its pressure becomes half. Since on the lake, the pressure is equal to the atmospheric pressure, hence the pressure of air inside the bubble at the depth of lake = 2 atmospheric pressure = atmospheric pressure + pressure due to column of water h. thus <br>

of water

76 cm of Hg = h cm

= 76 cm of Hg

=76 xx 13.6 cm of water

=1033.6 cm = 10.34 m

Answered by s7a2352vidya00192
0

As volume of air bubble becomes double on reaching the surface of lake, hence its pressure becomes half. Since on the lake, the pressure is equal to the atmospheric pressure, hence the pressure of air inside the bubble at the depth of lake = 2 atmospheric pressure = atmospheric pressure + pressure due to column of water h. thus <br>

of water

76 cm of Hg = h cm

= 76 cm of Hg

=76 xx 13.6 cm of water

=1033.6 cm = 10.34 m

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