An aircraft executes a horizontal loop at a speed of 120km/hr with its wings banked at 15 degree. What is the radius of the loop?
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Answered by
2
formula from banking...
tan$=v^2/rg
r=416m
tan$=v^2/rg
r=416m
Answered by
0
## Explaination-
# Given-
v = 120 km/h = 100/3 m/s
θ = 15°
# Solution-
For circular motion with inclination θ, we have
tanθ = v^2 / rg
Putting values,
tan15 = (100/3)^2 / (r×10)
r = 1000/(0.268 *9)
r = 14925/36m
Radius of the loop is14925/36 km.
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