Question

An airplane flies against the wind from A to B in 8 hours. The same airplane returns from B to A, in the same direction as the wind, in 7 hours. Find the ratio of the speed of the airplane (in still air) to the speed of the wind. 

Answer 1

let speed of plane = x km/h
speed of wind = y km/h

we know, speed = distance /time
let L is the distance between A and B

according to question ,
equation when plane moves in opposite direction

L/( x - y) = 8 ----------(1)

again, equation when , plane moves in same direction .

L/( x + y) = 7 -----------(2)

divide (1) by (2)

(x + y)/( x - y) = 8/7

7(x + y) = 8( x - y)

7x + 7y = 8x - 8y

(8 -7)x = (7 + 8)y

x = 15y

x/y = 15/1

Answer 2

Solution:-

Let speed of plane in still air be x and speed of wind be y

7(x+y) = 8( x-y)

7x+7y = 8x - 8y

x= 15y

ANSWER ratio = 15:1

Explanation:

Hope it helps you