an alpha particle is accelerated through a potential difference of 10^6 V. its kinetic energy will be......................??
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Potential difference = 10^6 V
Q = 2 * 1.6 * 10^-19 C = 3.2 * 10^-13 C
Kinetic Energy = V * Q = 2 * 1.6 * 10^-19 * 10^6
= 3.2 * 10^-13 J
This will be the kinetic energy.
The charge of a particle will be twice than an electron hence, the charge will be doubled.
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