an aluminium has diameter 0.5 millimetre and resistivity is 2.8 × 10 to power 6 ohm how much length of this why is required to make a 10 ohm coil
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Resistance = resistivity × length/area
diameter = 0.5 mm = 0.05 cm = 5× 10^-4 m
radius = 2.5 × 10^-4
Area = pie r^2 = 3.14× 6.25 × 10^ -8
= 19.625× 10^-8
R = 2.8× 10^-6× L/ 19.625× 10^-8
R = 2.8 × 10^2 × L/19.625
10 × 19.625 = 2.8× 10^2 L
196.25/2.8 × 10^2 = L
70.08 × 10^-2m = L
0.7008 m= L
✌❤Dr.Dhruv❤✌
deepika6006:
I don't get it
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