Question

An aluminum wire contains 5.5×10^25 atoms of aluminum . calculate the number of moles of aluminum​

Answer 1

Answer:

1 mole of aluminium atoms contains 6.022 × 10²³ atoms.

It can also be written as:

6.022 × 10²³ atoms have number of moles = 1

Therefore, 5.5 × 10²⁵ atoms have number of moles:

$\implies \rm n_{(Al)} = \dfrac{1}{6.022 \times 10^{23}} \times 5.5 \times {10}^{25}$

$\implies \rm n_{(Al)} = \dfrac{5.5 \times {10}^{25} }{6.022 \times 10^{23}}$

$\implies \rm n_{(Al)} = \dfrac{5.5 \times {10}^{25} \times {10}^{ - 23} }{6.022 }$

$\implies \rm n_{(Al)} = \dfrac{5.5 \times {10}^{2} }{6.022 }$

$\implies \rm n_{(Al)} = 0.9133\times {10}^{2}$

$\implies \rm n_{(Al)} = 9.133\times {10}^{ - 1} \times {10}^{2}$

$\implies \underline{ \boxed{ \bf n_{(Al)} = 9.1 33\times {10}^{ 1}}}$

Answer 2

Answer:

91.33 moles

Explanation:

91.33 is simply answer of moles beacuse of 10^2 means 2number right side