Math, asked by ShivamPayla211, 1 month ago

an amount of 50000 is out into three investments at the rate of 6%, 7%, 8% respectively. the total annual income is 3580. if the combined income from the first two investments is 70 more than the income from the third. find the amount invested in each type of investment separately.

Answers

Answered by minasj223
0

Answer:

Let investments be x, y, z.

x=

100

6×5000

=300

y=

100

7×5000

=350

z=

100

8×5000

=400

Now,

6x+7y+8z=100 ………(1)

x+y+z=358 ……(2)

x+y−z=70 ………(3)

Δx=B

6

1

1

7

1

1

8

1

−1

x

y

z

=

100

358

70

=Δ=

6

1

1

7

1

1

8

1

−1

=(−6+8+7)−(8+6−7)

=9−7=2

Δ

1

=

100

358

70

7

1

1

8

1

−1

=(−100+358×8+490)−(560+100−7×358)

=−70+15×358

=5300

Δ

2

=

6

1

1

100

358

70

8

1

−1

=(−6×358+100−560)−(8×358+420−100)

=−14×358+660−320

=−4672

Δ

3

=

6

1

1

7

1

1

100

358

70

=(1420+100+7×358)−(100+6×358+490)

=288

x=

Δ

Δ

1

=

2

5300

=2650

y=

Δ

Δ

2

=

2

−4672

=2336

z=

Δ

Δ

3

=

2

288

=144

Amount of each investment is Rs. 2650, Rs. 2336, Rs. 144.

Step-by-step explanation:

hope this helps you dear

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