Question

An amount of rs.1,00,000 is invested in two types of shares. the first yields an interest of 9% p.a. and the second, 11% p.a. if the total interest at the end of one year is 9¾%, then the amount invested in each share was

Answer 1

Always apply the formula dear.

Answer 2

Answer:

Let x be the amount invested ( in rupees ) in first share,

∵ Total invested amount = rs 1,00,000

So, the amount invested in the second share = 100000-x

Now, there is 9% p.a. interest in first share,

Thus, the interest by first share= $\frac{x\times 9}{100}$

$=0.09x$

( ∵ one year interest formula, $I=\frac{P\times r}{100}$

Where, P = principal amount, r = annual rate )

Similarly, there is 11% p.a. interest in second share,

Thus, the interest by second share = 0.11(100000-x)

So, the total interest in one year = 0.09x + 0.11(100000-x)

= 11000-0.02x

According to the question,

Total amount earned 9¾%, interest,

$\implies  11000-0.02x = \frac{9.75\times 100000}{100}$

$11000-0.02x = 9750$

$\implies  0.02x = 11000 - 9750\implies x = \frac{1250}{0.02}=62500$

Hence, investment in first share = rs 62,500

In second share = 100000 - 62500 = rs 37,500