An angle is 30 degrees more than one-half of its complement.find the angles in degree
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Answered by
15
Hey there,
Let the angle be x
then other angle is 30+x/2
x+30+x/2=90
3x/2=60
3x=120
x=40 So the other angle is 90-40=50
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
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07161020
Ace
Let the angle be x
then other angle is 30+x/2
x+30+x/2=90
3x/2=60
3x=120
x=40 So the other angle is 90-40=50
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
Answered by
8
Hi there !
Let one of the angles be "x" , and the other angle be "30+x/2"
A.T.Q.,
x+ (30+x)/2 = 90
3x/2 = 60
3x = 120
x = 40
x/2 + 30 = 40/2 + 30 = 50
The angles are of measures 40° and 50°
Let one of the angles be "x" , and the other angle be "30+x/2"
A.T.Q.,
x+ (30+x)/2 = 90
3x/2 = 60
3x = 120
x = 40
x/2 + 30 = 40/2 + 30 = 50
The angles are of measures 40° and 50°
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