Question

An anti-tank gun fires a shell with a velocity of 98V2 m/s at an elevation of 45° to the horizontal
and the shell strikes a tank which is advancing with a velocity of 30 m/s directly towards the gun
in the same horizontal plane as the gun. Find the distance between the gun and the tank at the
instant when the gun was fired. g= 9.8 m/s2.
(2560 m)​

Answer 1

Explanation:

ANSWER

Mass of bullet

m=0.05 Kg

v=1000m/s

F=200N

Force on the man is equal to the change in momentum of the bullets coming out of the gun

F= t

mvn

200=

1

0.5×1000×n

n=4persecond

n=240perminute