an ap consists of 50 terms of which 3rd term is 12 and last term is 106 find the 29th term
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a50= a+49d
106= a+49d --》1
a3= a+2d
12= a+2d --》 2
solving 1 and 2
a + 49d = 106
a + 2d = 12
- - -
47d= 94
d = 2 in 2
a+2 (2) =12
a+ 4= 12
a = 12-4
a= 8
a29= a+28d = 8+28 (2) = 8+ 56 = 64
106= a+49d --》1
a3= a+2d
12= a+2d --》 2
solving 1 and 2
a + 49d = 106
a + 2d = 12
- - -
47d= 94
d = 2 in 2
a+2 (2) =12
a+ 4= 12
a = 12-4
a= 8
a29= a+28d = 8+28 (2) = 8+ 56 = 64
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