Question

An aqueous solution containing 1.248 g of bacl2 in 100g of water boils at 100.0832 degree celsius .calculate degree of dissociation.

Answer 1

An aqueous solution is a solution in which the solvent is water.

It is mostly shown in chemical equations by appending (aq) to the relevant chemical formula.

An aqueous solution containing 12.48g of barium chloride in 1000g of water, boils at 100.0832o100.0832oC0.

(KbKb for water is 52Kkgmol−10.52Kkgmol−1, at. Wt. Ba+137, CI=35.5 wBaCl2wBaCl2=12.48 g; wH2OwH2O= 1000 g; ΔTbΔTb= 0.0832 K; KbKb=0.52 Kkg/mol

ΔTb=iKbmm=wBaCl2MBaCl2×1000wH2Om=12.48208×10001000=0.06i=0.08320.52×0.06=2.7Also,i=NumberofmolesatequillibriumBaCl21−x⇌Ba2+x+2Cl−2xi=1−x+x+2x=1+2x=2.7x=0.85ΔTb=iKbmm=wBaCl2MBaCl2×1000wH2Om=12.48208×10001000=0.06i=0.08320.52×0.06=2.7Also,i=NumberofmolesatequillibriumBaCl21−x⇌Ba2+x+2Cl−2xi=1−x+x+2x=1+2x=2.7x=0.85

Therefore degree of dissociation is 85%