Question

An aqueous solution of glucose has osmotic pressure 2.72 atm at 298 k how many moles of glucose dissolve per litre of the solution

Answer 1

HEYA GM ❤

WE KNOW THAT ;

PV = nRT

Here ;

P/RT = n/V

2.72 / 0.0821 × 298 = n/V of Glucose

★ n/V = 0.111 M

# Moles of Glucose Dissolved in 1L of soln is 0.111 M.

Answer 2

Answer:

Moles of glucose dissolve per liter of the solution is $0.111 M$.

Explanation:

It is given that

$P=2.72atm$

$T=298K$

We know the relation

By general gas equation

$PV=nRT$

Giving values will give us $\frac{2.72}{0.821*298} =\frac{n}{V}$ moles of glucose dissolved per liter

Solving above we get,

$\frac{n}{V} =0.111M$

Hence, number of moles of glucose dissolve per liter of the solution is $0.111M$

#SPJ2