an archer shoots an arrow horizontally with an initial velocity of 100 M per second from a building that is 20 m high (air resistance is neglected). The time when the arrow is in the air and the horizontal distance that the arrow Travels before striking the ground is
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for the total time that particle is on air= √2h/g
so, √2×20÷20=2s
and for the total horizontal distance which is equal to range we have the relation t=r/u
so,. 2×100=200m
Hope that helps
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