Question

in the diagram given below O is the centre of the circle chord CD is parallel to diameter AB if angle ABC =35° calculate angle CED

Answer 1

Answer:

see the image

hope it helps you ☺️

Answer 2

Given ∠ABC=35⁰

Now, ∠AOC subtended by the chord AC at the centre O of circle will be double the ∠ABC subtended by same chord AC at point B on corresponding segment of circle thus

∠AOC=2∠ABC=2×35⁰ =70⁰

∠BOD=∠AOC=70⁰

But

∠AOC+∠COD+∠BOD=180⁰

70⁰ +∠COD+70⁰ =180⁰

∠COD=40⁰

Now, ∠COD subtended by the chord CD at the centre O of circle will be double the ∠CED subtended by same chord CD at point E on corresponding segment of circle thus

∠COD=2∠CED

40⁰=2∠CED

∠CED=20⁰