Question

an army contingent of 616 members is to march behind an army band of 32 members in a parade the two groups are to march in the same number of columns. what is the maximum number of columns in which they can march
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Answer 1

We need to find the hcf of these two numbers. Since this ques is from class 10th

Let's do it via EDL method

Since 616>32

a = 616

b = 32

a = bq + r

616 = 32×19 + 8

32 = 8×4 + 0

Hence the HCF is 8

Therefore they can march in 8 columns each.

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Given:

• Number of army contingent members = 616
• Number of army band members = 32

If the two groups have to march in the same column, we have to find out the highest common factor between the two groups. HCF(616, 32), gives the maximum number of columns in which they can march.

By Using Euclid’s algorithm to find their HCF, we get,

Since, 616 > 32, therefore,

616 = 32 × 19 + 8

Since, 8 ≠ 0, therefore, taking 32 as new divisor, we have,

32 = 8 × 4 + 0

Now we have got remainder as 0, therefore, HCF (616, 32) = 8.

• Hence, the maximum number of columns in which they can march is 8.