Question

An array S[10] [30] is stored in the memory along the column with each of its element occupying 2 bytes. Find out the memory location of S[5][10], if element S[2][15] is stored at the location 8200.

Answer 1

Here is your answer.

use the formula

address = B+W ((I-Lc)N+(J-Lr))

where B is base address

W is element size

Lc and Lr are lower and upper. bound of array

M and N are rows amd columns

Answer 2

The memory location of S[5][10] is 8106

Given,

ASSUMING LBR=2

LBC=15

B = 8200

To Find

The memory location of S[5][10]

Solution

W=2 BYTES, NUMBER OF ROWS(M)=10, NUMBER OF COLUMNS(N)=30

LOC(S[I][J]) = B +((I-LBR) + (J-LBC)*M)*W

LOC(S[5][10])= 8200 + ((5-2) + (10-15)*10)*2

= 8200 + (3 + (-5)*10) * 2

= 8200 + (3 + (-50)) * 2

= 8200 + (3 – 50) * 2

= 8200 + (-47) * 2

= 8200 – 94

= 8106

Hence , the memory location of S[5][10] is 8106

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