Question

· An arrow is fixed straight up, leaving the bow at 15 m/s. If air resistance is negligible, how high will the
arrow rise

(a) 10.5 m
(b) 15.0 m
(c) 11.25 m
(c) 8.5 m​

Answer 1

Answer:

11.25 m

Explanation:

An arrow is vertically projected with velocity 15 m/s

Air resistance is negligible then the maximum height that it can reach is given by the formula :-

u²/2g.

Initial velocity of the bow = 15

= 15²/2 × 10

= 225/20

= 11.25 m

So the maximum height it can reach is 11.25 m

Answer 2

Answer:

Hmax=u^2 / 2g

= 15^2/ 20

= 225 / 20

= 11.45 m

Hence maximum height attained will be 11.45 m

Hope it helps:)