An assembly hall is 45 m long, 30 m broad and 16 m high. It has five doors, each measuring 4 m
by 3.5 m and four windows 2.5 m by 1.6 m each. Find
i) the cost of papering its walls at the rate of ₹ 35 per m²;
i) the cost of carpeting its floor at the rate of ₹ 154 per m2.
Answers
Answer:
So guys here is your answer
Area of 4 walls of the room = [2(l+b)*h] sq.units
So, Area of the 4 walls of the room which is to be papering is = [2(45+30)*16] m^2
Now the area of the four walls is = 2400 m^2
Now we have to find the area of both the five doors and four windows . So here we as follow,
Area of five doors = (4*3.5)m^2 = 14 cm^2
As there are five doors so we have to multiply 14 with 5 , so = (14*5)m^2 = 70 m^2 is the area of the five doors .
Now, Area of four windows =(2.5*1.6)m^2 = 4m^2 is the area of 1 window. As we are having &
4 windows we would multiply 4 with 4 , so
area of four windows is =(4*4)m^2 = 14m^2
Now, area not to be papered = ( Area of the doors)+(Area of the windows) = (14+70)m^2 = 86 m^2 is the area of both the doors and windows and also the area which not to be papered .
Now area to be papered = ( Area of the 4 walls )-(Area of the doors and windows)
= (2400-86)m^2 = 2314 m^2 come the area to be papered . Now ,
1 m^2 of wall would cost ₹ 35 to get papered ;
2314 m^2 of wall would cost = ₹(2314*35) to get papered. so the cost to paper the walls of the assembly is ₹80990
Now, We know that to find the floor area , we just have to multiply the length and breadth of the walls of the assembly or =(l*b) cube.units.
So , the area is = (45*30) m^2 = 1350 m^2.
Now,
1m^2 of the floor will cost ₹154 to carpet it.
1350m^2 of the floor will cost =₹(1350*154)
= ₹ 207900 is the cost to carpet the floor of the assembly hall.
So , here are the two answers finally,
the cost of papering the wall = ₹ 80990.
the cost of carpeting the floor = ₹ 207900.
hope that this helps you.
please mark my answer as the brainliest
Step-by-step explanation:
ananajjajsjsjjsjskakkkskksksksjsjdjjdjsjjsjdd
