Physics, asked by prasadrohan662, 6 months ago

An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 minutes 20 s?​

Answers

Answered by Premchess
4

Answer:

And the displacement is 200 m .

I have attached solution in photo .

Please mark me the brainliest if you like my solution .

Attachments:
Answered by jevelin
1

Answer:

Answer:-

Distance covered = 2200 m

Displacement = 200 m

Given:-

Diameter of track = 200 m

Radius of track = \frac{200}{2}

2

200

= 100 m

Time taken by the athlete to cover 1 round = 40 s

Explanation:-

Distance covered by athlete in one round = 2πr

⇒ 2 × ( \frac{22}{7}

7

22

) × 100

Speed of the athlete = \frac{Distance}{Time}

Time

Distance

⇒ (2 × 2200) / (7 × 40)

⇒ 4400 / 7 × 40

So, Distance covered in 140 s = Speed × Time

⇒ 4400 / (7 x 40) x (2 x 60 + 20)

⇒ 4400 / ( 7 x 40) x 140

⇒ 4400 x 140 /7 x 40

⇒ 2200 m

No. of rounds in 140 s

= \frac{140}{40}

40

140

= 3\frac{1}{2}

2

1

At the end of his motion, the athlete will be in the diametrically opposite position.

Or, displacement = diameter = 200 m

Explanation:

hope it's will help u

Similar questions