Physics, asked by mohitkumar99130, 7 months ago

An athlete completes one round of circular track of diameter 100m in 40sec.

What will be the displacement and distance covered at the end of 2min 20 sec.​

Answers

Answered by siddhusujhatha
0

Answer:The diameter of the circular track is given as 200 m. That is, 2r=200 m.

From this radius is calculated as Radius, r = 100 m.

In 40 sec the athlete complete one round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds.

One round is considered as the circumference of the circular track.

The distance covered in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m.

For each complete round the displacement is zero. Therefore for 3 complete rounds, the displacement will be zero.

At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.

Hence, the distance covered is 2200 m and the displacement is 200 m.

Explanation:

Answered by jaishika07
0

Answer:

displacement=100m

no of round taken by the athlete= 3.5. [ 2m20s/40s]

distance covered=1099.7m

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