An athlete jogs along a circular track of radius 2R. If the athlete jogs 2 complete rounds, calculate distance and displacement. pls pls help me I will mark the first person to answer as brainliest
Answers
Answer:
Hello mate
Explanation:
The diameter of the circular track is given as 200 m. That is, 2r=200 m.
From this radius is calculated as Radius, r = 100 m.
In 40 sec the athlete complete one round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds.
One round is considered as the circumference of the circular track.
The distance covered in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m.
For each complete round the displacement is zero. Therefore for 3 complete rounds, the displacement will be zero.
At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.
Hence, the distance covered is 2200 m and the displacement is 200 m.
Given :
▪ Radius of circular path = 2R
▪ Athlete completes two rounds.
To Find :
▪ Distance
▪ Displacement
Concept :
❇ Distance is defined as the length of actual path traversed by the body
❇ It is a scalar quantity
❇ It can't be negative or zero.
❇ It has only magnitude.
❇ SI unit : m
✴ Displacement is defined as the shortest distance b/w initial and final position.
✴ It is a vector quantity.
✴ It has both magnitude as well as direction.
✴ It can be positive, negative or zero.
✴ SI unit : m
⭐ Distance ≥ Displacement ⭐
Calculation :
☣ Distance :
☞ Distance = 2(circumference)
☞ Distance = 2[2π(2R)]
☞ Distance = 8πR
☣ Displacement :
Since, athlete comes back to the initial position after 2 rounds displacement will be equal to zero.
☞ Displacement = zero