Question

an echo is returning in 3sec.what is the distance of reflecting surface from the source. given that speed of sound is 342

Answer 1

t=1.5sec
v=342m/s
distance d=v*t
d=1.5*342
d=513m

Answer 2

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Speed of sound, v = 342 m s−1

Echo returns in time, t = 3 s

Distance travelled by sound = v × t = 342 × 3 = 1026 m

In the given time interval, sound has to travel a distance that is twice the distance of the reflecting surface and the source.

Hence, the distance of the reflecting surface from the source = (1026/2)m= 513m

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