An electric bulb is rated 220v - 100 what is the resistance if 5bulbs are burn for 4hoirs
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220÷100=2.2
2.2×5×4=44
2.2×5×4=44
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Rating of bulb = 220 v - 100 A .
Potential difference = 200 v
Current = 100 A
Power = 100 A × 220 V
= 22000 W.
I²Rt = 22,000 W × t
= > I²R = 22,000 W
= > 100² × R = 22,000 W
= > R = 22,000 ohms/ ( 100 × 100 )
= > R = 22,000 / 10,000
= > R = 22/10
= > R = 2.2
The resistance is 2.2 ohms
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