Question

An electric bulb marked 15 V is connected to a battery
of 15 V which has a negligible resistance. If the
resistance offered by the bulb is 5 Ω the power of the
bulb is _____W.
(a) 225 (b) 75
(c) 30 (d) 45

Answer 1

Answer:

45W

Explanation:

in the for the bulb the resistance generated;

V=IR

15= I × 5

I= 3A ---> 1.

w.k.t power 'P' consumed by the bulb is expressed by;

P=VI

P= 15 × 3 (FROM 1.)

So, P= 45 W

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