an electric dipole of dipole 20*10^-6m is enclosed by a closed surface. what is the net flux coming out of the surface?
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4
its flux will be zero
souravsinha:
but how?
because flux q/ۥ and total charge enclosed is zero
pls make me as brainlist
shure
Hey mark brainliest
thnxx bro
Answered by
6
Hey
In my opinion, it's answer should be zero because flux lines are originated from positive charge and sink on negative charge.
No matter what the dipole moment is. Since a dipole contains both, positive and negative charge, flux will originate from positive charge and sink on negative charge and since both charges are inside the closed surface , the net flux crossing the surface should be zero.
Total charge inside the enclosed surface =q-q=0
So the net flux=0
i hope it help you
mark brainliest
In my opinion, it's answer should be zero because flux lines are originated from positive charge and sink on negative charge.
No matter what the dipole moment is. Since a dipole contains both, positive and negative charge, flux will originate from positive charge and sink on negative charge and since both charges are inside the closed surface , the net flux crossing the surface should be zero.
Total charge inside the enclosed surface =q-q=0
So the net flux=0
i hope it help you
mark brainliest
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