Question

An electric heater of power 3 KW is used for 10 h.how much energy does it consume? Express your answer in KWh and joule.

Answer 1

Answer:

Given,

Power (P) = 3kW

= 3000 W

Time (t) = 10 hrs

Units Consumed = Pt/1000

= (3000*10)/1000 kWh

The Units Consumed is 30 kWh.

1 kWh = 3.6*10⁶ J

30 kWh = (3.6*30)*10⁶ J

= 1.08*10⁸ J

I hope this helps.

Answer 2

Power = 3 kW = 3000 W

Time = 10 h = 36000 s

${ \green{ \bf{ P=E/T }}}$

${ \green{ \bf{ E=P×T }}}$

E=3000×36000

E = 108000000J

${ \green{ \bf{ In\: Joule \: = 1.08×10⁸J }}}$

1kWh = 3600000J

${ \green{ \bf{ So, }}}$

108000000/3600000

${ \green{ \bf{ In \: kWh \: =30kWh \: Ans }}}$